Worksheet

Worksheet: real numbers, absolute value, integer and fractional part

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Summary

The absolute value of a number measures its distance to zero: $|x| = x$ when $x \ge 0$ and $|x| = -x$ when $x < 0$. The integer part $[x]$ is the greatest integer not exceeding $x$, and the fractional part $\{x\} = x - [x]$ always lies between $0$ and $1$. The worksheet trains evaluation, properties and equations with absolute value.

Press “Check” next to an exercise. Your answers stay on this device.

This worksheet has 30 problems grouped into the three performance levels from the national assessment standards (basic – consolidated – advanced). Each section has calculations, properties, equations and inequalities. Write complete solutions; the criteria used to grade a solution are given below.

Evaluation criteria

Level Items Performance descriptors – the student:
Basic 1 – 10 computes the absolute value, the integer part and the fractional part of given numbers (including negative or irrational ones); recognizes the basic properties; solves equations and inequalities of the form $|ax + b| = c$, $|ax + b| \leq c$, $\lbrack x\rbrack = k$, in a familiar mathematical context.
Consolidated 11 – 22 removes the absolute value after determining the sign; justifies properties; solves equations of the type $|E| = |F|$, $|E| = F$ (with a condition), sums of absolute values (the interval method), inequalities whose solutions are unions of intervals, and equations/inequalities with $\left\lbrack E(x) \right\rbrack$, in varied contexts.
Advanced 23 – 30 proves inequalities using the properties of absolute value; discusses the number of solutions depending on a parameter; solves equations with nested absolute values, equations of the type $\left\lbrack E(x) \right\rbrack = F(x)$ or with $\lbrack x\rbrack$ and $\left\{ x \right\}$; generalizes a calculation, in a complex context.

A complete solution meets: C1 – identifying the type of problem and writing the conditions (the sign of the expression, the right-hand side non-negative, $k \in {\mathbb{Z}}$, $\left\{ x \right\} \in \lbrack 0,\ 1)$); C2 – correctly applying the definitions and properties; C3 – the correctness of the calculations; C4 – the write-up: intersecting with the conditions, writing the solution set $S$ (a finite set, an interval or a union of intervals) and checking it.

Section A – Basic level (items 1 – 10)

Write complete solutions.

Calculations

  1. Calculate $| - 7| + |3 - 8| - | - 2| \cdot |4|$.

  2. Show that $\left| \sqrt{5} - 3 \right| + \left| \sqrt{5} - 2 \right| = 1$.

  3. Calculate $\left\lbrack \text{3,7} \right\rbrack$, $\left\lbrack - \text{3,7} \right\rbrack$, $\left\{ \text{3,7} \right\}$ and $\left\{ - \text{3,7} \right\}$.

  4. Find $\left\lbrack \sqrt{20} \right\rbrack$, $\left\lbrack - \sqrt{20} \right\rbrack$ and $\left\{ \sqrt{20} \right\}$.

Properties

  1. Determine whether each statement is true or false. Justify with a property or with a counterexample.

    a) $|a + b| = |a| + |b|$, for any $a,\ b \in {\mathbb{R}}$;

    b) $|x|^{2} = x^{2}$, for any $x \in {\mathbb{R}}$;

    c) $\sqrt{x^{2}} = x$, for any $x \in {\mathbb{R}}$;

    d) $\lbrack x + 2\rbrack = \lbrack x\rbrack + 2$, for any $x \in {\mathbb{R}}$;

    e) $\lbrack 2x\rbrack = 2\lbrack x\rbrack$, for any $x \in {\mathbb{R}}$.

  2. Show that $|x - 3| + |x + 1| = 4$, for any $x \in \lbrack - 1,\ 3\rbrack$.

Equations

  1. Solve in $\mathbb{R}$ the equation $|x - 2| = 5$.

  2. Solve in $\mathbb{R}$ the equations:

    a) $|2x + 1| = - 3$;

    b) $|3x - 6| = 0$.

  3. Find the real numbers $x$ for which $\lbrack x\rbrack = - 2$.

Inequalities

  1. Solve in $\mathbb{R}$ the inequalities and write the solution set as an interval:

    a) $|x - 1| \leq 3$;

    b) $\lbrack x\rbrack < 3$.

Section B – Consolidated level (items 11 – 22)

Write complete solutions.

Calculations

  1. Show that the number $N = \left| 1 - \sqrt{2} \right| + \left| \sqrt{2} - \sqrt{3} \right| + \left| \sqrt{3} - 2 \right|$ is a natural number.

  2. Show that $\sqrt{x^{2} - 2x + 1} + \sqrt{x^{2} - 8x + 16} = 3$, for any $x \in \lbrack 1,\ 4\rbrack$.

  3. Calculate $S = \left\lbrack \sqrt{1} \right\rbrack + \left\lbrack \sqrt{2} \right\rbrack + \left\lbrack \sqrt{3} \right\rbrack + \ldots + \left\lbrack \sqrt{10} \right\rbrack$.

Properties

  1. Let $a,\ b \in {\mathbb{R}}$ with $|a| \leq 1$ and $|b| \leq 1$. Show that:

    a) $|a + b| \leq 2$;

    b) $|ab| \leq 1$.

  2. a) Show that $\lbrack x\rbrack + \lbrack - x\rbrack = - 1$, for any $x \in {\mathbb{R}} \smallsetminus {\mathbb{Z}}$.

    b) Calculate $\left\lbrack \sqrt{3} \right\rbrack + \left\lbrack - \sqrt{3} \right\rbrack + \left\{ \sqrt{3} \right\} + \left\{ - \sqrt{3} \right\}$.

Equations

  1. Solve in $\mathbb{R}$ the equation $|2x - 3| = |x + 1|$.

  2. Solve in $\mathbb{R}$ the equation $|x - 3| = 2x - 1$.

  3. Solve in $\mathbb{R}$ the equation $|x - 1| + |x - 2| = 3$.

  4. Solve in $\mathbb{R}$ the equation $\left\lbrack \frac{2x + 1}{3} \right\rbrack = 2$.

Inequalities

  1. Solve in $\mathbb{R}$ the inequality $|2x - 5| > 3$.

  2. Consider the set $A = \{ x \in {\mathbb{R}}\text{ | }1 \leq |x - 2| < 4\}$.

    a) Write the set $A$ as a union of intervals.

    b) Find the set $A \cap {\mathbb{Z}}$.

  3. Solve in $\mathbb{R}$ the inequality $\left| 2\lbrack x\rbrack - 1 \right| \leq 3$.

Section C – Advanced level (items 23 – 30)

Write complete solutions, with all justifications.

Properties and proofs

  1. The real numbers $x$ and $y$ satisfy $|x - 2| \leq 1$ and $|y + 1| \leq 2$. Show that $|x + 2y| \leq 5$.

  2. Consider the expression $E(x) = |x - 1| + |x + 2|$, where $x \in {\mathbb{R}}$.

    a) Show that $E(x) \geq 3$, for any $x \in {\mathbb{R}}$, and find the values of $x$ for which $E(x) = 3$.

    b) Discuss, depending on the values of the real parameter $m$, the number of solutions of the equation $E(x) = m$.

Equations

  1. Solve in $\mathbb{R}$ the equation $\left| |x - 2| - 3 \right| = 1$.

  2. Solve in $\mathbb{R}$ the equation $\lbrack x\rbrack = \frac{3x - 1}{2}$.

  3. Solve in $\mathbb{R}$ the equation $\lbrack x\rbrack + 2\left\{ x \right\} = 3$.

Inequalities

  1. Solve in $\mathbb{R}$ the inequality $|x + 1| - |x - 2| \geq 1$.

Synthesis problems

  1. a) Check the equality $\lbrack x\rbrack + \left\lbrack x + \frac{1}{2} \right\rbrack = \lbrack 2x\rbrack$ for $x = \text{2,3}$ and for $x = \text{2,7}$, then prove that it holds for any $x \in {\mathbb{R}}$.

    b) Solve in $\mathbb{R}$ the equation $\lbrack x\rbrack + \left\lbrack x + \frac{1}{2} \right\rbrack = 5$.

  2. (Top-grade problem)

    a) Show that, for any $k \in {\mathbb{N}}^{*}$, there are exactly $2k + 1$ natural numbers $n$ with $\left\lbrack \sqrt{n} \right\rbrack = k$.

    b) Calculate $S = \left\lbrack \sqrt{1} \right\rbrack + \left\lbrack \sqrt{2} \right\rbrack + \left\lbrack \sqrt{3} \right\rbrack + \ldots + \left\lbrack \sqrt{99} \right\rbrack$.

Self-assessment

Section Items solved correctly The criterion I missed most often (C1–C4) What I should review from the summary
A – basic …… out of 10
B – consolidated …… out of 12
C – advanced …… out of 8

Frequently asked questions

How do you remove the absolute value in a computation?

Check the sign of the expression inside the bars: if it is positive or zero, write it unchanged, and if it is negative, flip its sign. For example, $|3 - 7| = 4$, because $3 - 7 = -4$. The same rule applies when the bars enclose an expression with letters.

Why does the equation $|x| = -2$ have no solution?

Because the absolute value of any real number is greater than or equal to zero, so it can never equal a negative number. In general, an absolute-value equation has solutions only when the right-hand side is positive or zero, and then it is solved by cases, according to the sign of the expression inside the bars.