Worksheet

Worksheet: neighbourhoods and accumulation points

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Summary

A set is a neighbourhood of a point when it catches an open interval around it, and for $+\infty$ or $-\infty$ it must catch a ray. An accumulation point draws points of the set into each of its neighbourhoods, while an isolated point stays alone in a small enough neighbourhood. The worksheet trains spotting neighbourhoods and classifying points.

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Remember

  • $V$ is a neighbourhood of $x_{0} \in {\mathbb{R}}$ if $\exists\varepsilon > 0$ such that $\left( x_{0} - \varepsilon,x_{0} + \varepsilon \right) \subset V$.
  • $V$ is a neighbourhood of $+ \infty$ if $\exists a \in {\mathbb{R}}$: $(a, + \infty) \subset V$; of $- \infty$ if $\exists a \in {\mathbb{R}}$: $( - \infty,a) \subset V$.
  • $x_{0} \in \overline{\mathbb{R}}$ is an accumulation point of $A$ if every neighbourhood of $x_{0}$ contains a point of $A$ different from $x_{0}$. $A'$ = the set of accumulation points.
  • $a \in A$ is an isolated point of $A$ if $a \notin A'$.
  1. Decide which of the following sets are neighbourhoods of the point $x_{0} = 2$; justify.

    a) $V_{1} = (1,3)$;

    b) $V_{2} = \lbrack 2,5\rbrack$;

    c) $V_{3} = (0,4\rbrack \smallsetminus \left\{ 3 \right\}$;

    d) $V_{4} = {\mathbb{Z}}$;

    e) $V_{5} = \left( - \infty,2 + \frac{1}{100} \right)$;

    f) $V_{6} = {\mathbb{R}} \smallsetminus \left\{ 2 \right\}$.

  2. Which of the following sets are neighbourhoods of $+ \infty$?

    a) $(5, + \infty)$;

    b) $\mathbb{N}$;

    c) $\lbrack - 3, + \infty) \smallsetminus \left\{ 10 \right\}$;

    d) ${\mathbb{R}} \smallsetminus \lbrack 0,1\rbrack$;

    e) $( - \infty,100)$.

  3. Find the set of accumulation points $A'$ and the isolated points of the set $A$:

    a) $A = \lbrack - 1,3)$;

    b) $A = (0,1) \cup \left\{ 2,3 \right\}$;

    c) $A = \left\{ \frac{1}{n}\mkern6mu \middle| \mkern6mu n \in {\mathbb{N}}^{*} \right\}$;

    d) $A = {\mathbb{Z}}$;

    e) $A = \left\{ 1,2,3 \right\}$.

  4. Find $a \in {\mathbb{R}}$ for which the set $V = (a - 2,2a + 1)$ is a neighbourhood of $3$.

  5. (optional) Let $A = \left\{ \frac{( - 1)^{n}}{n}\mkern6mu \middle| \mkern6mu n \in {\mathbb{N}}^{*} \right\}$. Show, using the definition, that $0$ is an accumulation point of $A$ and find $A'$.

Frequently asked questions

Is every open interval a neighbourhood of each of its points?

Yes. When $x_0 \in (a, b)$, you can fit a small interval $(x_0 - d, x_0 + d)$ inside $(a, b)$ by taking $d$ below the distances to the endpoints. That is exactly why the neighbourhood definition asks for an open interval around the point, not necessarily centred on it.

Can an isolated point also be an accumulation point?

No, the two notions exclude each other: an isolated point of $A$ owns a neighbourhood with no other points of $A$, while an accumulation point finds points of $A$ in every neighbourhood. A point of $A$ is either an accumulation point or an isolated one, with nothing in between.